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设g(x),f(x)在[a,b]上连续,且g(x)非负,f(x)>0,求
设g(x),f(x)在[a,b]上连续,且g(x)非负,f(x)>0,求
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设g(x),f(x)在[a,b]上连续,且g(x)非负,f(x)>0,求
设f∈C([a,b]).若有定义在[a,b]上的函数g(x):g(x)=f(x),a.e.x∈[a,b],试问g(x)在[a,b]上必是几乎处处连续的吗?
A.∫abf(x)dx≥∫abg(x)dx;
B.∫abf(x)dx≤∫abg(x)dx;
C.∫f(x)dx≥∫g(x)dx;
D.∫f(x)dx=∫abg(x)dx
设f(x),g(x)在区间[-a,a](a>0)上连续,g(x)为偶函数,f(x)满足f(x)+f(-x)=A(A为常数).试证
并用该等式计算积分;
设f(x)及g(x)在[a,b]上连续,证明
(1)若在[a,b]上,f(x)≥0,且f(x)dx= 0,则在[a,b]上f(x)=0;
(2)若在[a,b]上,f(x)≥0,且f(x)≠0,则f(x)dx>0;
(3)若在[a,b]上,f(x)≤g(x),且f(x)dx=
g(x)dx, 则在[a,b]上f(x)=g(x).
设f(x),g(x)在[0,1]上的导数连续,且f(0)=0,f(x)≥0,g(x)≥0.证明:对任何a∈[0,1],有 ∫0ag(x)f(x)dx+∫01f(x)g(x)dx≥f(a)g(1)。
A.f(x)在[a,b]上恒等于g(x)
B.在[a,b]上至少有一个使f(x)≡g(x)的子区间
C.在[a,b]上至少有一点x,使f(x)=g(x)
D.在[a,b]上不一定存在x,使f(x)=g(x)