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[单选题]
若函数f(x)的定义域为[-1,5],则函数g(x)=f(x+2)+f(x-1)的定义域是()
A.[0,3]
B.[-3,6]
C.[-3,0]
D.[3,6]
查看答案
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)
A.[0,3]
B.[-3,6]
C.[-3,0]
D.[3,6]
A.若任取x1,x2∈D,当x1<x2时,f(x1)<f(x2),则y=f(x)在D上是增函数
B.函数y=x²在R上是增函数
C.函数y=-1/x在定义域上是增函数
D.函数y=1/x的单调递减区间是(-∞,0)∪(0,+∞)