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[单选题]
若函数f(x+1)=x(x-1),则f(x)=()。
A.x(x+1)
B.(x-1)(x-2)
C.(x-1)
D.(x-1)(x+1)
查看答案
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A.x(x+1)
B.(x-1)(x-2)
C.(x-1)
D.(x-1)(x+1)
若f(x-1)=x2-x,则f(x)= ( )
(A)x2+x (B)x(x-1) (C)(x-1)2-(x-1) (D)(x+1)(x-2)
若多项式f(x)=x3+a2x2+x-3a能被x-1整除,则实数a=().
A.0
B.1
C.0或1
D.2或-1
E.2或1