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The Case of the Disappearing Fingerprints
One useful anti-cancer drug can effectively erase the whorls(萝状指纹)and other characteristic marks that give people their distinctive fingerprints．Losing them could become troublesome．A case【51】______online in a letter by Annals of Oncology indicates how big a【52】______losing finger prints is．
Eng-Huat Tan，a Singapore-based medical doctor describes a 62-year-old man who has used capecitabine(卡培他滨)to【53】______his nasopharyngeal cancer(鼻咽症)．After three years on the【54】______，the patient decided to visit his U．S．relatives last December．But he was stopped by U．S． customs officials【55】______4 hours after entering the country when those officials couldn't get finger prints from the man．There were no【56】______swirly(旋涡状的)marks appearing from his index fin ger．
U．S．customs has been fingerprinting incoming foreign visitors for years，Tan says．Unfortunately， for the Singaporean traveler，one potential【57】______effect of his drug treatment is a smoothing of the tissue on the finger pads．【58】______，no fingerprints．
“It is uncertain when fingerprint【59】______will begin to take place in patients who are taking capecitabine，”Tan points out．So he【60】______any physicians who prescribe the drug to provide their patients with a doctor's【61】______pointing Out that their medicine may cause fingerprints to disappear．
Eventually，the Singaporean traveler made it into the United States．But he's also now got the explanatory doctor's note-and won't leave home【62】______it．
By the way，maybe the Food and Drug Administration，【63】______approved use of the drug 11 years ago，should consider updating its list of side effects【64】______with this medicine．The current list does note that patients may experience vomiting(呕吐)，stomach pain and some other side effects． But no where【65】______it mention the potential for loss of fingerprints．
(51)
A．released
B．suggested
C．accepted
D．detected
A.tan（a +π/3） = tan a +tanπ/3
B.tan（a +π/3） = （tan a+tanπ/3）/（1+tan a tanπ/3）
C.tan（a +π/3） = （tan a+tanπ/3）/（1－tan a tanπ/3）
D.tan（a +π/3） =（tan a－tanπ/3）/（1+tan a tanπ/3）
A.tan（x+y） = tan x+tan y
B.tan（x+y） = （tan x+tan y）/（1+tanx tany）
C.tan（x+y） = （tan x+tan y）/（1－tanx tany）
D.tan（x+y） = （tan x－tan y）/（1+tanx tany）
