题目内容
(请给出正确答案)
[单选题]
某电能表,其电表常数为2000r/kWh,测得10转的时间为12s,那么功率为()。
A.6kW
B.3kW
C.1.5kW
D.12kW
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A.6kW
B.3kW
C.1.5kW
D.12kW
A.200kWh
B.60kWh
C.12000kWh
D.600kWh
A.36
B.72
C.54
D.81
A.40%
B.60%
C.66.70%
D.100%
A.倍率=600/5×66000/100=7920
B.倍率=600×66000=39600000
C.倍率=600/5×66000=7920000
D.倍率=600×66000/100=396000
A.1000
B.400
C.200
D.100
A.-63.9%
B.63.9%
C.-23.9%
D.-13.6%
A.18
B.0.3
C.24
D.2.4
A.:-50%
B.:-55%
C.:-65%
D.:-73%