A.123451234
B.1234512345
C.1234554321
D.123455432
有下列程序: inta=4; intflintn) {intt=0;staticinta=5; if(n%2){inta=6;t+=a++;} else{inta=7;t+=a++;} returnt+a++; } main() {ints=a,i=0; for(;i<2;i++)s+=f(i); printfl%d\n,s); } 程序运行后的输出结果是
A.28
B.24
C.32
D.36
main()
{inta[]={1,2,3,4,5,6,7,8,9,10},s=0,i;
for(i=0;i<10;i++)
if(a[i]%2==0)s=s+a[i];
printf("s=%d",s);
}
程序运行结果是:______
A.&[2][1]
B.*(a[2]+1)
C.a[2]+1
D.*(a+2)+1
A.a=%2,b=%5
B.a=2,b=5
C.a=%%d,b=%%d
D.a=2,b=%d