A.123451234
B.1234512345
C.1234554321
D.123455432
A.inta=b=c=10
B.inta,b,c=10
C.a=10,b=10,c=10
D.a=b=c=10
main()
{inta[]={1,2,3,4,5,6,7,8,9,10},s=0,i;
for(i=0;i<10;i++)
if(a[i]%2==0)s=s+a[i];
printf("s=%d",s);
}
程序运行结果是:______
设inta=10,*p=&a;,则执行printf("%d\n",*p+a);的结果是()
A.10
B.20
C.30
D.40
#include<stdio.h>
main()
{inta[]={1,2,3,4},i,j,s=0;
j=1;
for(i=3;i>=0;i--){s=s+a[i]*j;j=j*10;}
printf("s=%d\n",s);
}
程序运行结果是:______
A.144
B.140
C.28
D.不能执行
A.b[3]
B.*(b+3)
C.p[1][3]
D.p[0][3]
有下列程序: structS{intn;inta[20];); voidflint*a,intn) {inti; for(i=0;i<n-1;i++)a[i]+:i; ) main() {inti;structSs={10,{2,3,1,6,8,7,5,4,10,9}); f(s.a,s.n); for(i=0;i<s.n;i++)printf(”%d,”,s.a[i]); ) 程序运行后的输出结果是
A.3,4,2,7,9,8,6,5,11,10,
B.2,3,1,6,8,7,5,4,10,9,
C.2,4,3,9,12,12,11,11,18,9,
D.1,2,3,6,8,7,5,4,10,9