![](https://static.youtibao.com/asksite/comm/h5/images/m_q_title.png)
[单选题]
设f(x)=x2+bx-3,且f(-2)=f(0),则f(x)≤0的解集为()
A.(-3,1)
B.[-3,1]
C.[-3,-1]
D.(-3,-1]
![](https://static.youtibao.com/asksite/comm/h5/images/m_q_a.png)
B、[-3,1]
![](https://static.youtibao.com/asksite/comm/h5/images/solist_ts.png)
A.(-3,1)
B.[-3,1]
C.[-3,-1]
D.(-3,-1]
B、[-3,1]
设f(x)=a(x-1)2-bcosx,且f(0)=1,f'(0)=2,则a=______,b=______。
设f(x)是以2为周期的周期函数,且f(x)又是偶函数,已知在[0,1]上f(x)=x2-2x,则=______.
设f在x=0连续,且对任何x,y∈R有
证明:(1)f在R上连续;(2)f(x)=f(1)x
设f(x)为连续函数,且,证明:
(1)若f(x)为偶函数,则F(x)也为偶函数;
(2)若f(x)为非增函数,则F(x)为非减函数。