更多“有如下VB程序段:s=0For i=1 To 5S=s+1N…”相关的问题
第1题
有如下VB程序段:s = 0For i = 1 To 15s = s + i Mod 2Next iLabel1.Caption = Str(s)该程序运行后,在标签Label1中显示的是()
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第2题
某VB 程序段如下:i = 1: s = ""Do While i <= 3k = i j = i + 1Do While j <= 8If a(j) < a(k) Then k = jj = j + 1LoopIf i < > k Thent = a(i): a(i) = a(k): a(k) = tn = n + 1End Ifs = s + Str(a(i)) : i = i + 1LoopLabel1.Caption = Str(n) + ":" + s数组a(1)到a(8)依次为:“16, 19, 8, 20, 4, 12,6, 15”,程序运行后,标签中显示的值为()
A.2:4 6 8
B.2:8 6 4
C.3:4 6 8
D.3:8 6 4
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第3题
有如下VB程序段:a(1) = 1:a(2) =1:b(1) =1:b(2 ) = 2For i = 3 To 5a(i) = a(i-1) + a(i-2)b(i) = b(i-1) + a(i)Next i执行该程序段后,数组元素b(5)的值为()
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第4题
某排序算法的VB程序段如下:k = 1For i = 1 To 2For j = 1 To 6 - 2 * iIf k * a(j) < k * a(j + 2) Thent = a(j)a(j) = a(j + 2)a(j + 2) = tEnd Ifk = -kNext jNext i数组元素a(1)到a(6)的初始值依次为“15,11,58,38,26,9”,该程序段执行后,数组元素a(1)到a(6) 的值分别为()
A.58,9,26,11,15,38
B.58,38,26,11,15,9
C.15,38,26,11,58,9
D.58,38,26,15,11,9
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第5题
某 VB 程序段如下:i = 1Do While i <= 3k = ij = i + 1Do While j <= 5If a(j) < a(k) Then k = jj = j + 1LoopIf i <> k Then t = a(i)a(i) = a(k)a(k) = tEnd Ifi = i + 1Loop数组元素a(1)到a(5)的值依次为“17,87,36,22,45”,则该程序段运行后,数组元素a(1)到a(5)的数据依次是()
A.87, 45, 36, 17, 22
B.17, 22, 36, 45, 87
C.17, 22, 36, 87, 45
D.87, 45, 17, 36, 22
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第6题
某VB 程序段如下:i = 1Do While i <= 3min= ij = i + 1Do While j <= 6If a(j) < a(min) Then min= jj = j + 1LoopIf i <> min Then t=a(i): a(i)=a(min): a(min)=ti = i + 1Loop数组元素a(1)到a(6)的值依次为“7, 8, 3, 9, 6, 2”,则上面程序段在运行后,数组元素a(1)到a(6)的数据依次是()
A.9, 8, 7, 3, 6, 2
B.2, 3, 6, 7, 8, 9
C.2, 3, 6, 9, 8, 7
D.9, 8, 7, 6, 3, 2
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第7题
下列程序段的执行结果为()。N=0For I=1 To 3For J =5 To 1 Step-1N= N+1Next J,IPrint N;J;I
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第8题
有如下所示的Java程序段:int total = 0;for (int i = 0; i < 4; i++ ){if (i == 1) {continue;}if (i == 2){break;}total += i;}total的值最后是多少
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第9题
下列程序执行后变量c的值为()c = 0For i = 1 To 10If i Mod 2 = 0 or i mod 3 = 1 Thenc = c + 1End IfNext i
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第10题
下面程序段执行后,变量s和i的值分别是()。inti,si=1,s=0while(s+=i++,i<=10)
A.55和10
B.55和11
C.45和10
D.55和11
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第11题
下面程序段运行的结果为()。#includeint f();int f(){static int i=0;int s=1;s+=i;i++; return s;}void main(){int i,a=0;for(i=0;i<5;i++) a+=f(); printf("%d/n",a);}
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